LEIPOLE · ENGINEERING TOOLS
Cabinet Cooling Fan Airflow Calculator
Choose what your enclosure needs, enter a few numbers and get LEIPOLE product recommendations instantly.
3Recommended products
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View the airflow in 3D
Products modelled from LEIPOLE FKL5525 CAD data. Airflow is not a CFD simulation or an IP-rating assessment.
How the selector calculates
Effective cabinet surface area follows IEC TR 60890 for the selected installation (arrangements A–G; covered sides count at a reduced factor, the floor not at all). U is 5.5 W/m²K for painted steel, 4.5 stainless steel, 12 aluminum, 3.5 plastic and 1.5 for a cabinet with 20–30 mm insulation. A safety factor of 1.2 is applied once in each method.
Cooling: Q need = heat loss × 1.2 − U × area × (max. inside − ambient). Required airflow = 3.1 × Q need ÷ (max. inside − ambient), matched against filter-fan airflow with the outlet filter fitted. Filter fans are recommended when the difference is at least 5 °C and one fan (up to 1,056 m³/h) or two in parallel can deliver the airflow; otherwise an enclosure air conditioner with a cooling capacity of at least Q need (rated at L35/L35, up to 7,500 W per unit).
Heating: heater power = (U × area × (min. inside − lowest ambient) − idle heat) × 1.2. Anti-condensation: heater power = (U × area × margin − idle heat) × 1.2, with the inside kept 5 °C above ambient (8 °C when very humid or with large day–night swings). Up to 150 W the selector recommends PTC heaters without a fan, above that fan heaters; beyond the largest single heater (950 W) two or three identical units, or insulation. A JSK0013 hygrostat (set to 65 % RH) or JSK0011R thermostat switches the heater.
Dust, humidity extremes, solar gain and altitude are not included. Confirm supply voltage, cut-out, protection rating and operating limits against the selected model’s datasheet.